Kinematics Problem Solver - Example 3

Question: A boy fired his M16 rifle to a tree. It is known that the muzzle velocity(velocity of the bullet) of his rifle is 975 m/s. The bullet is later found in the tree at a depth of 0.15m. Find the deceleration of the bullet.

(Air resistance is negligible.)

Answer:

From the question, we know that

• Initial velocity = 975 ms^-1.
• Final velocity = 0 ms^-1.
• Displacement = 0.15m.
• Deceleration = ?

Neat.

Now, let's enter these information into the program.

Fantastic.

-3.16875e+006 is -3.16875*10^6. 

Small 'e' stands for exponent.

The problem is solved and 

the answer is "Acceleration is -3.16875*10^6 ms^-2." which means that the deceleration of M16's bullet is 3.16875*10^6 ms^-2.

Well done.

Continue to example 4 for more on how to use this program!