Kinematics Problem Solver - Example 4

Question: A boy dropped a ball from a cliff. Find the ratio of distance fallen in the first 4 seconds to the distance fallen in the first 2 seconds by the ball.

Answer:

From the question, we know that

• Initial velocity = 0 ms^-1.
• Time taken = 2 s and 4 s.
• Acceleration = 10 ms^-2.
• Displacement = ?

Neatly done.

Now, to find the ratio of the time taken of two different falls, we will have to run the program twice as such.

Distance fallen in the first 2 seconds of the ball is 20 m.

Distance fallen in the first 4 seconds of the ball is 80 m.

Let's put them in the ratio as the question wants us to do it.

distance fallen in the first 4 seconds : distance fallen in the first 2 seconds = 80:20 = 4:1.

The answer is 4:1.

Easy to use, isn't it?

Continue to example 5 for more! (coming soon)

Kinematics Problem Solver - Example 3

Question: A boy fired his M16 rifle to a tree. It is known that the muzzle velocity(velocity of the bullet) of his rifle is 975 m/s. The bullet is later found in the tree at a depth of 0.15m. Find the deceleration of the bullet.

(Air resistance is negligible.)

Answer:

From the question, we know that

• Initial velocity = 975 ms^-1.
• Final velocity = 0 ms^-1.
• Displacement = 0.15m.
• Deceleration = ?

Neat.

Now, let's enter these information into the program.

Fantastic.

-3.16875e+006 is -3.16875*10^6. 

Small 'e' stands for exponent.

The problem is solved and 

the answer is "Acceleration is -3.16875*10^6 ms^-2." which means that the deceleration of M16's bullet is 3.16875*10^6 ms^-2.

Well done.

Continue to example 4 for more on how to use this program!

Kinematics Problem Solver - Example 2

Question: A boy throws a ball vertically with a velocity of 2.0 m/s. What is the time taken for the ball to reach back to his hand?

Answer:
From the question, we know that

• initial velocity = 2.0 m/s. (It was thrown with "a velocity of 2.0 m/s.")
• final velocity = -2.0 m/s. (It fell "back to his hand.")
• acceleration = -10 m/s^2. (Acceleration due to gravity, taking upwards as positive.)
• time = ?

Neatly done.
Now, let's enter these information into the program as follow.

Fabulous.

The program neatly solved for you. The answer is 0.4s.

Check out the example 3 for more!

Kinematics Problem Solver - Example 1

Question: A car, moving at constant speed of 50 m/s, decelerates uniformly before it stops. The time taken to stop is 2.5 seconds. What is the distance travelled by car when stopping?

Answer:

From the question, we know that

• Initial velocity = 100 ms^-1. (Given)
• Final velocity = 0 ms^-1. (Inferred. "It stops.")
• Time = 2.5 s. (Given)
• Displacement = ?

Neatly done.
Now, let's enter these information into the program as follow.

Great.

The program solved for you. The answer is 62.5m.

Extra: The program even solved for other information(like acceleration and average velocity) using the given points.

Check out the example 2 for more!

Kinematics Problem Solver - Download

Before you download..

If you are using this for the first time, please read an article on how to use it.
You can also take a look at examples on how this program is used to solve problems.

If you are ready to try out, you can download it from here.

DOWNLOAD

Thank you for trying.

For bug reports and version issues, please click here.
You can contact the developer at theomoe@gmail.com.

Kinematics Problem Solver - About & How to use it

About.

This program solves high school Kinematics problems that are one dimensional.
This program is written in C++ language.

How to use.

To try it out, please download the .exe file and double-click it to start.
To get it to solve a problem, you will have to tell the program three things:

1. the points that are given in the question and the values of the given points.
2. the points that are not given in the question and
3. what the question is asking for.

The program will solve the answer for you if the correct information is entered.

Please take a look at the examples to see how it works.

One-sentence term and condition.

   The software, developed single-handedly by the author of this blog, is meant to be a completely free software and therefore, feel free to use, study and modify the codes, or redistribute the software, and be completely assured that the developer will never trouble you with copyright laws for his codes.

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